MATH 5345H --- Week 11: The Urysohn lemma, metrization, and Tietze extension

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0.1  (§33) The Urysohn lemma

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    ★ Thm. (Urysohn’s lemma.) A,B disjoint closed subsets of a normal space X ⇒ there is a map f:X→[0,1] with f≡0 on A and f≡1 on B.

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    Proof, on the board in four moves.

    1. (1)

      Dyadic rationals r=a/2n are dense in ℝ.

    2. (2)

      Build a nested family. U1=X−B; normality gives U0 with A⊂U0⊂U¯0⊂U1, then U1/2 between them. Inductively insert U(2⁢b+1)/2n between U2⁢b/2n and U(2⁢b+2)/2n. Result: U¯p⊂Uq whenever p<q. Extend by Ur=∅ for r<0 and Ur=X for r>1.

    3. (3)

      Define D⁢(x)={r⁢ dyadic∣x∈Ur} and f⁢(x)=infD⁢(x)∈[0,1].

    4. (4)

      Three claims. (a) x∈U¯r⇒f⁢(x)≤r;  (b) x∉Ur⇒f⁢(x)≥r;  (c) f is continuous.

    Proof. For (c): given (c,d)∋f⁢(x), pick dyadic c<p<f⁢(x)<q<d; then U=Uq−U¯p is a neighborhood of x with f⁢(U)⊂(c,d).

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    Def. A,B are separated by a continuous function if some f:X→ℝ is 0 on A and 1 on B. (Forces A∩B=∅.)

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    Def. X is completely regular (T3⁤12) if points are closed and each point and disjoint closed set are separated by a continuous function.

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    Lem. Normal ⇒ completely regular ⇒ regular.

    Proof. First: Urysohn with A={x}. Second: U=f−1⁢[0,12), V=f−1⁢(12,1].

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    Thm. Subspaces and products of completely regular spaces are completely regular. Caution. The same is not true for normality.

0.2  (§34) The Urysohn metrization theorem

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    ★ Thm. Every second-countable regular space is metrizable.

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    Proof: embed X into ℝω (product topology, which is metrizable).

    1. (1)

      Claim 1: a countable separating family. There are maps fk:X→[0,1] such that for every p∈U open, some fk has fk⁢(p)=1 and fk⁢(X−U)⊂{0}.

    2. (2)

      Construction. {Bn} a countable basis. For each pair (m,n) with B¯m⊂Bn, use Urysohn (X is normal by Thm 32.1) to get gm,n with gm,n⁢(B¯m)={1}, gm,n⁢(X−Bn)={0}. Reindex as {fk}.

    3. (3)

      Claim 2: F⁢(x)=(f1⁢(x),f2⁢(x),…) is an embedding X→ℝω. Continuous (components are); injective (separate x from y using U=X−{y}).

    4. (4)

      Claim 3: F is open onto its image Z. Given q=F⁢(p)∈F⁢(U), choose k with fk⁢(p)=1, fk⁢(X−U)={0}, and set W=Z∩πk−1⁢(0,∞). Then q∈W⊂F⁢(U).

    Note. Regularity is used exactly once — to produce p∈Bm⊂B¯m⊂Bn, which is what makes the pair (m,n) available.

0.3  (§35–§36) Tietze extension; manifolds

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    ★ Thm. (Tietze.) A closed in a normal X. Every map A→[0,1] (resp. A→ℝ) extends to a map X→[0,1] (resp. X→ℝ). [Mk §35]

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    ★ Def. An m-manifold is a second-countable Hausdorff space in which every point has a neighborhood homeomorphic to an open subset of ℝm (equivalently, to ℝm itself).

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    Notation. m=0: discrete countable set. m=1: curve. m=2: surface.

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    Thm. A compact m-manifold embeds in ℝn for some n. [Mk §36]