MATH 5345H --- Week 3: Topological spaces and standard examples

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1  Topological Spaces and Continuous Functions

1.1  (§12) Topological spaces

  •  Def. A topology on a set X is a collection 𝒯 of subsets with

    1. (1)

      𝒯 and X𝒯;

    2. (2)

      {Uα}αJ𝒯αJUα𝒯 (arbitrary unions)

    3. (3)

      U1,,Un𝒯U1Un𝒯 (finite intersections)

    (X,𝒯) is a topological space; the U𝒯 are the open sets.

    Note.For (3) it is enough to check n=2; induct. The asymmetry between (2) and (3) is the whole subject — infinite intersections of open sets need not be open: n(1/n,1/n)={0}.

  • Def. Discrete 𝒯disc=𝒫(X) (every subset open). Trivial 𝒯triv={,X}.

  • Ex. X={a,b}: exactly four topologies — 𝒯triv,   𝒯a={,{a},X},   𝒯b={,{b},X},   𝒯disc. The middle two are the Sierpiński topologies.

    Note.In (X,𝒯a): a is separated from b, but every open set containing b contains a. So a is “arbitrarily close” to b without b being close to a. No metric does this.

  • Ex. X={a,b,c}: there are 29 topologies. Nine of them, the rest obtained by permuting a,b,c:

    • {,X}

    • {,{a},X}

    • {,{a,b},X}

    • {,{a},{a,b},X}

    • {,{a,b},{c},X}

    • {,{a},{b},{a,b},X}

    • {,{a},{a,b},{a,c},X}

    • {,{a},{c},{a,b},{a,c},X}

    • 𝒫(X), the discrete topology (8 elements)

  • Ex. Not topologies on {a,b,c}: {{a},{c},{a,b},{a,c}} (misses ,X); {,{a},{b},X} (no union); {,{a,b},{a,c},X} (no intersection).

  • Def. 𝒯 is coarser than 𝒯 (𝒯 finer) if 𝒯𝒯. Always 𝒯triv𝒯𝒯disc.

    Note.A partial order, not a total one: neither Sierpiński topology refines the other.

  • Def. Cofinite topology: 𝒯cof={UXXU finite}{}. It is a topology.

    Proof. (2): if some Uβ then XUαXUβ is finite. (3): De Morgan turns XUi into a finite union of finite sets.

  • Rmk. X finite 𝒯cof=𝒯disc;  X infinite 𝒯cof𝒯disc (singletons are not cofinite). On : 𝒯triv𝒯cof𝒯disc.

  • Def. A metric on X is d:X×X with

    1. (1)

      d(x,y)0, with d(x,y)=0x=y;

    2. (2)

      d(x,y)=d(y,x);

    3. (3)

      d(x,z)d(x,y)+d(y,z).

    ε-ball: Bd(x,ε)={yd(x,y)<ε}.

  •  Def. Metric topology 𝒯d: U open for each xU there is ε>0 with Bd(x,ε)U. This is a topology.

    Proof. (3) is where finiteness enters: take ε=min{ε1,,εn}>0. An infinite family would give inf=0.

1.2  (§13) Basis for a topology

  •  Def. , a collection of subsets of X, is a basis if

    1. (1)

      each xX lies in some B;

    2. (2)

      xB1B2 there is B3 with xB3B1B2.

  • Def. Topology generated by : U𝒯xUB:xBU. This is a topology.

  • Ex. Open discs in 2;  open rectangles (a,b)×(c,d);  singletons {x} (generating 𝒯disc).

    Proof. For rectangles, B1B2 is again a basis element or empty — condition (2) is free. For discs it needs the triangle inequality.

  • Lem. Let be a basis for 𝒯. Then (1) each B is open; (2) every open U is a union of basis elements: U=xUBx.

    Note.The gluing trick — assemble local choices Bx into one global object. It recurs throughout the course; name it now.

  •  Lem. (Recognition criterion.) Let 𝒞 be a collection of open sets in (X,𝒯) such that for every open U and every xU there is C𝒞 with xCU. Then 𝒞 is a basis for 𝒯.

    Note.The workhorse for identifying bases. Use it for products, subspaces, metric subspaces.

  •  Lem. (Comparison.) , bases for 𝒯,𝒯. TFAE:

    1. (1)

      𝒯𝒯;

    2. (2)

      for each B and xB there is B with xBB.

  • Caution. 𝒯𝒯 does not require — only that has smaller sets near each point.

  • Cor.  and generate the same topology both conditions hold: for each xB there is B with xBB, and for each xB there is B with xBB.

  • Ex. Discs and rectangles generate the same topology on 2, namely the metric topology.

  • Def. Standard topology on : basis {(a,b)a<b}; equals 𝒯d for d(x,y)=|yx|.

  • Def. Lower limit topology 𝒯 on : basis {[a,b)a<b}; write .

  • Lem. 𝒯d𝒯.

    Proof.: given x(a,b) take [x,b). Strict: no (c,d) sits inside [a,b) around x=a, since (c+a)/2 escapes.

  • Def. A subbasis 𝒮 is a collection of subsets with S𝒮S=X. Its associated basis is ={S1SnSi𝒮,n1}; the topology generated by 𝒮 is the one generated by . Always 𝒮𝒯.

    Proof. satisfies the basis axioms: (2) holds because B1B2 is again a finite intersection of subbasis elements. The bound n1 avoids the empty intersection.