0.1 (§18) Continuous functions
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Def. is continuous if is open in for every open . A continuous function is called a map.
Note. Refer back to §2: preimages respect , , . Images do not. That is the entire reason the definition takes this form.
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Lem. Composites of maps are maps.
Proof. .
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Lem. It is enough to test a basis: continuous open for all . And enough to test a subbasis: open for all .
Proof. Because commutes with unions (basis) and with finite intersections (subbasis).
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Ex. Metric spaces: continuity for all and there is with . The – definition, recovered.
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Ex. is not continuous ( is not open in ); is continuous.
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Def. is continuous at if for each neighborhood of there is a neighborhood of with .
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Thm. continuous continuous at every .
Proof. is the gluing trick again: .
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Thm. TFAE:
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is continuous;
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for every ;
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is closed for every closed .
Proof. via the neighborhood criterion for closure; apply to ; complement.
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Def. is a homeomorphism if it is bijective and both and are continuous. Then , topologically equivalent.
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Lem. is an equivalence relation (identity, inverse, composite).
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Lem. For bijective, TFAE: homeomorphism; open in open in ; open in open in .
Note. So a homeomorphism is a bijection of the topologies, not just of the points.
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Def. A topological property is one expressible in terms of points and open sets; such properties are preserved by homeomorphism. E.g. finiteness, discreteness, Hausdorff, and later compactness and connectedness.
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Ex. via .
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Ex. via , . Hence every open interval .
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Caution. Continuous bijection homeomorphism.
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.
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, . Here is open in but is not open in : no neighborhood of lies inside it.
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Constructing maps.
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Thm. The subspace topology on is the coarsest making the inclusion continuous.
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Cor. Restrictions of maps are maps. Lem. Corestrictions (with ) are maps.
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Def. is an embedding if the corestriction is a homeomorphism onto the subspace .
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Lem. is an embedding with a homeomorphism onto a subspace and the inclusion. Embeddings are injective.
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Ex. , : injective and continuous, not an embedding.
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Lem. Maps to a one-point space are continuous; hence constant maps are continuous.
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Thm. (Pasting lemma.)
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with all open: continuous every continuous.
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with all closed (finitely many): continuous every continuous.
Proof. Open case: , a union of open sets. Closed case: same with closed sets — and now finiteness is essential.
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Thm. (Maps into a product.) is continuous both components and are continuous.
Proof. Subbasis criterion: , .
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Cor. The product topology is the coarsest topology making both projections continuous.
0.2 (§19) The product topology (general)
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Def. On the product topology is generated by the subbasis
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Lem. Concretely:
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subbasis elements are with for at most one ;
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basis elements are with for finitely many .
Note. Emphasise “all but finitely many coordinates unrestricted”. This is the point where students expect the naive definition and get a different one.
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Thm. continuous every component is continuous.
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Cor. The product topology is the coarsest making all continuous.
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Thm. subspaces: on , product topology subspace topology from .
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Thm. All Hausdorff Hausdorff.
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Thm. .